Mole Ratios

A balanced equation is like a recipe. A recipe tells you how much of each ingredient to put in a cheesecake (or whatever). A balanced equation tells you how many of each molecule are involved in the reaction.

Let’s say a cheesecake recipe takes four cream cheese, three eggs, and one cup of sugar. It’s a balanced equation for cheesecake:

4\,Cream Cheese + 3\,Egg + 1\,Sugar \rightarrow 1\,Cheesecake

Food Ratio Problem 1: What if you need to make 5 cheesecakes? How many packages of cream cheese do you need to buy?

Answer: You need four cream cheese for every one cheesecake. You can write that ratio as a fraction:

\left(\cfrac{4\,Cream Cheese}{1\,Cheesecake}\right)

If this was a chemistry problem that you couldn’t do in your head, you would multiply the amount of cheesecake you want by this fraction to get the answer:

(Known Amount) x (Mole Ratio) = Answer

5\,Cheesecake\times\left(\cfrac{4\,Cream Cheese}{1\,Cheesecake}\right) = 20\, Cream Cheese

You need 20 packages of cream cheese.

This was setup to make “Cheesecake” units cancel out on the bottom of the mole fraction like this:

5\,\cancel{Cheesecake}\times\left(\cfrac{4\,Cream Cheese}{1\,\cancel{Cheesecake}}\right) = 20\, Cream Cheese

Here’s another type of problem: let’s say I have 24 packages of cream cheese. What’s the right number of eggs to go with 24 packages of cream cheese?

Food Ratio:

\left(\cfrac{3\,Egg}{4\,Cream Cheese}\right)

This time cream cheese goes on the bottom since we want it to cancel out when we calculate the answer:

(Known Amount) x (Mole Ratio) = Answer

24\,\cancel{Cream Cheese}\times\left(\cfrac{3\,Egg}{4\,\cancel{Cream Cheese}}\right) = 18\, Egg

The math involved is simply this: 24\times\left(\cfrac{3}{4}\right)=18

Mole Ratios / Chemical Reaction Recipes

Coefficients in a balanced chemical equations show mole ratios.

Example Balanced Equation:

2KClO_3 \rightarrow 2KCl + 3O_2

The “2” in “2KClO3” is the first coefficient in this equation.

Mole Ratio Example Questions
Example 1: If 12 moles of KClO3 are used up, how many moles of O2 are produced?

Mole Ratio:

\left(\cfrac{3\,mol\,O_2}{2\,mol\,KClO_3}\right)

    • We have KClO3 on the bottom since so it will cancel out.
    • O2 is on top since that’s what we want to calculate.
    • The “3” in “3O2” comes from the balanced equation.
    • The “2” in “3KClO3” comes from the balanced equation.

     

  • (Known Amount) x (Mole Ratio) = Answer

    12\,\cancel{mol\,KClO_3} \times \left(\cfrac{3\,mol\,O_2}{2\,\cancel{mol\,KClO_3}}\right) = 18\,mol\,O_2