Food Molecule Quiz

1. What type of food molecule is this?

\definesubmol{n}{H_2N-[,.7]CH} \definesubmol{a}{-[,.7]C(=[1]O)} \definesubmol{try2}{!n([6]-CH_2-[,.6]*5(-(*6(-=-=-))=-NH-[,,1]=))!a} \chemfig{[,0.6]!{try2}-[7]OH}
 
 
 
 
 

Question 1 of 12

2. What type of food molecule is this?

\definesubmol{a}{-C(-[2,.4])(-[6,.4])} \definesubmol{d}{-C(-[6,.4])=C(-[6,.4])} \definesubmol{e}{-C(-[2,.4])=C(-[2,.4])} \definesubmol{s}{-O-C(=[6]O)} \definesubmol{FA}{!s!a!a!e!a!a!d!a!a!e!a!a-[,.4]} \chemfig{[,.5]C(-[4,.4])(-[2,.4])(!{FA}) -[6,1.2]C(-[4,.4])(!{FA}) -[6,1.2]C(-[4,.4])(-[6,.4])(!{FA})}
 
 
 
 
 

Question 2 of 12

3. What type of food molecule is this?

\definesubmol{n}{-[,.7]N(-[2]H)-[,.7]C(-[2]H)} \definesubmol{a}{-[,.7]C(=[2]O)} \definesubmol{ile}{!n([6]-CH(-[7,0.7,1,1]CH_3)-[5,.7,1,1]CH_2-CH_3)!a} \chemfig{[,0.6]H!{ile}-OH}
 
 
 
 
 

Question 3 of 12

4. What type of food molecule is this?

\setcrambond{2pt}{}{} \definesubmol{e}{-[:-30,0.7]O-[:30,0.7]} \definesubmol{g}{ <[7,0.7](-[2,0.5]OH) -[,,,,line width=2pt](-[6,0.5]OH) >[1,0.7] (-[3,0.7]O -[4](-[2,0.3]-[3,0.5]OH) -[5,0.7])} \definesubmol{f}{ (-[2,0.5](-[3,.5]HO))(-[:30,1.2]O?[a]) <[7,.8](-[6,0.5]OH) -[,,,,line width=2pt](-[2,.5,,2]HO) >[1,.8]?[a](-[6,.6]-[7,.5]OH)} \chemfig{ (-[6,0.7,,2]HO)!g!e!f}
 
 
 
 
 

Question 4 of 12

5. What type of food molecule is this?

\definesubmol{a}{-C(-[2,.4])(-[6,.4])} \definesubmol{e}{-C(-[2,.4])=C(-[2,.4])} \definesubmol{s}{-O-C(=[2]O)} \definesubmol{FA}{!s!a!a!a!a!e!a!a!a!a!a-[,.4]} \chemfig{[,.5]C(-[4,.4])(-[2,.4])(!{FA}) -[6,1.2]C(-[4,.4])(!{FA}) -[6,1.2]C(-[4,.4])(-[6,.4])(!{FA})}
 
 
 
 
 

Question 5 of 12

6. What type of food molecule is this?

\chemfig{[:30,0.7]HS--[:-30](-[6]NH_2)-(=[2]O)-[:-30]OH}
 
 
 
 
 

Question 6 of 12

7. What type of food molecule is this?

\setcrambond{2pt}{}{} \chemfig[,1.4]{ C?[a](-[2,0.4])(-[6,0.5,,2]HO) <[7,1]C(-[6,0.4])(-[2,0.5]OH) -[,,,,line width=2pt]C(-[2,.4])(-[6,.5]OH) >[1,1]C(-[6,.4]) (-[3,1]O-[4]C?[a](-[2,0.8]C(-[,.5]OH)(-[4,0.4])-[2,0.4])(-[6,0.4])) -[,0.7]O -[,.7]C?[b](-[2,0.4]) <[7,1]C(-[6,0.4])(-[2,0.5]OH) -[,,,,line width=2pt]C(-[2,.4])(-[6,.5]OH) >[1,1]C(-[6,.4]) (-[3,1]O-[4]C?[b](-[2,0.8]C(-[,.5]OH)(-[4,0.4])-[2,0.4])(-[6,0.4])) -[,0.7]O -[,.7]C?[z](-[2,0.4]) <[7,1]C(-[6,0.4])(-[2,0.5]OH) -[,,,,line width=2pt]C(-[2,.4])(-[6,.5]OH) >[1,1]C(-[6,.4]) (-[3,1]O-[4]C?[z](-[2,0.8]C(-[,.5]OH)(-[4,0.4])-[2,0.4])(-[6,0.4])) -[2,0.5]OH }
 
 
 
 
 

Question 7 of 12

8. What type of food molecule is this?

\definesubmol{n}{-[,.7]N(-[2]H)-[,.7]C(-[2]H)} \definesubmol{a}{-[,.7]C(=[2]O)} \definesubmol{gly}{!n([6]-H)!a} \definesubmol{ala}{!n(-[6]CH_3)!a} \definesubmol{val}{!n([6]-CH(-[5,.7,,1]CH_3)-[7,.7,1]CH_3)!a} \definesubmol{leu}{!n([6,.8]-CH_2-CH(-[5,,,1]CH_3)-[7,,1]CH_3)!a} \definesubmol{ser}{!n([6,.6]-CH_2-OH)!a} \definesubmol{cys}{!n([6,.6]-CH_2-SH)!a} \chemfig{[,0.6]H!{ala}!{cys}!{val}-OH}
 
 
 
 
 

Question 8 of 12

9. What type of food molecule is this?

\definesubmol{a}{-[:30]-} \definesubmol{b}{-[:30]=[0]-} \chemfig{[:-30,0.6]HO-C(=[6]O)!a!a!a!a!a!a!a!a!a}
 
 
 
 
 

Question 9 of 12

10. What type of food molecule is this?

\definesubmol{n}{-[,.7]N(-[2]H)-[,.7]C(-[2]H)} \definesubmol{a}{-[,.7]C(=[2]O)} \definesubmol{val}{!n([6]-CH(-[5,.7,,1]CH_3)-[7,.7,1]CH_3)!a} \definesubmol{cys}{!n([6,.6]-CH_2-SH)!a} \chemfig{[,0.6]H!{val}!{cys}-OH}
 
 
 
 
 

Question 10 of 12

11. What type of food molecule is this?

\definesubmol{n}{-[,.7]N(-[2]H)-[,.7]C(-[2]H)} \definesubmol{a}{-[,.7]C(=[2]O)} \definesubmol{gly}{!n([6]-H)!a} \definesubmol{ala}{!n(-[6]CH_3)!a} \definesubmol{val}{!n([6]-CH(-[5,.7,,1]CH_3)-[7,.7,1]CH_3)!a} \definesubmol{leu}{!n([6,.8]-CH_2-CH(-[5,,,1]CH_3)-[7,,1]CH_3)!a} \definesubmol{ser}{!n([6,.6]-CH_2-OH)!a} \definesubmol{cys}{!n([6,.6]-CH_2-SH)!a} \definesubmol{asp}{!n([6]-CH_2-C(-[7]OH)=[5]O)!a} \definesubmol{asn}{!n([6]-CH_2-C(-[7,.7]NH_2)=[5,.7]O)!a} \definesubmol{met}{!n([6]-CH_2-CH_2-S-CH_3)!a} \chemfig{[,0.6]H!{gly}!{ser}-OH}
 
 
 
 
 

Question 11 of 12

12. What type of food molecule is this?

\definesubmol{a}{-C(-[2,.4])(-[6,.4])} \definesubmol{d}{-C(-[6,.4])=C(-[6,.4])} \definesubmol{u}{-C(-[2,.4])=C(-[2,.4])} \chemfig{[4,.6]C(=[7]O)(-[1,.6]OH)!a!a!a!d!a!u!a!a!d!a!a-[,.4]}
 
 
 
 
 

Question 12 of 12